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Boltzmann constant - DeBroglie principle

The Boltzmann constant defines the amount of energy of heat necessary to raise the temperature of a gas by one degree of temperature measured in degrees Kelvin, when at the pressure of one atmosphere. Boltzmann constant k is equal to:

k = 1.380658 x 10-23 J/K (Joule / Kelvin)

1J = 107 erg

1 erg = 1.6 x 1012 eV

k = 2.2 x 10-4 eV/K        k = 2.2 x 10-13 GeV / K

vP = 0.0044 C = 4.4 x 10-3 x 3 x 105 Km/sec

vP = 13.2 x 102 Km / sec = 1.32 x 103Km / sec = 1320 Km / sec = 1.32 x 106 m / sec

What additional velocity would be generated to a proton by an energy of

2.2 x 10-13 GeV for each Kelvin degree?

v2 / E2 = vl / E1      v2 = vl x E2 / E1     v1 = 0.0044C    1Km / sec = 10-6 x C

1 m = 1015 GeV-1     1 sec = 1024 GeV-1     E1 = 2.2 x 10-13 GeV    E2 = 10-5 GeV

v2 = 0.0044 C x 2.2 x 10-13 GeV / 10-5 GeV

v2 = 4.4 x 10-3 x 2.2 C x 10-8 = 9.68 x 10-11 C = 10-10 C

v2 = 10-10 x 3 x 105 Km / sec = 3 x 10-5 Km / sec = 0.03 m / sec

If my assumptions are correct, the additional velocity of a proton at rest for each additional input of energy equal to the Boltzmann constant is 3 cm / sec. The additional velocity increase of a proton under the influence of heat is

3 cm /sec for each degree of temperature K. At the temperature of 0 degree Celsius or 273 degrees Kelvin the velocity of a proton will be increased by 819 cm / sec. 

DeBroglie principle

The substance of matter can be envisioned for being some time represented by particles and sometime by waves, a paradox that scientists have tried to explain since the advent of the Planck theory. The American physicist Arthur Holly Compton discovered that X rays radiation (considered to be a very energetic electromagnetic wave) could in penetrating matter lose energy when hitting an Electron while imparting to it increased velocity and a change of direction. Compton experiment demonstrated that waves and particles can display similar physical properties. It was also experimentally discovered that a beam of Electrons in penetrating a crystal would display patterns of interference as observed by Young when light waves were projected through a screen with two adjacent slots. The French scientist Louis DeBroglie in considering the problem expressed the relationship of particles and waves in the formula:

Lambda = h / Mo v

Lambda represents the wave length of a speeding object, h the Planck constant, v the velocity of a moving object and Mo the mass of the object. The wavelength of an object in motion can be expressed as a function of the Planck constant h over its momentum Mo x v, a relationship that applies to all objects possessing momentum. I assumed that the transitional velocity of an Electron at its lowest energy level is provided by the energy contained in its non imploding volume M. The mass of an electron Mo is equal to 0.51 x 10-3 GeV. The mass of M (the non imploding mass of an Electron) is equal to 10-9 GeV. M also indicates the mass of an object (increasing or decreasing according to its velocity).

       h = 1         C = 1

From the equation

Lambda = h / Mo x v

The velocity of an electron at its lowest energy level is

0.7 x 10-6

Lambda = 1 / 10-3 GeV x 0.7 x 10-6 = 0.7 x 10-9 GeV-1

0.7 x 10-9 GeV-1 in meters is equal to 0.7 x 10-24 m

In DeBroglie equation the wavelength of an electron at its lower energy level has the same value that I assumed to be the diameter of the electron source. Coincidence?

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