In following with the same hypothetical
interpretation of the substance of matter we will now try to analyze the universal gravity constant G by using the same mathematical
considerations that we followed in the evaluation ofthe Planck constant. The value of the gravity constant was first determined
experimentally by Henry Cavendish at 6.67 x 10^{-11} m^{3} /Kg^{ }/ sec^{2}.

In
natural uni1m ^{3} = 10 -^{45} GeV ^{-3}

Ee ~ 0.51 x I0^{ -3} GeV

The mass of the electron
in grams is: 9.1 x 10 ^{-28} Kg = 10 ^{-27} Kg

It takes l0 ^{27} electron
masses to make 1 Kg. The energy of mass of one electron is equal to:

0.51 x I0 ^{-3} GeV

1 Kg = 0.51 x 10 ^{-3} GeV x 10 ^{27 / 10^-48 GeV^-2} = 0.51 x 10^{ -72}GeV
1 Kg = 0.51 x 10 ^24 GeV ^-1 / 10 ^-48 GeV ^-2 =

1 Kg = 0.51
x 10 x 10^-24 GeV = 0.51 x 10 ^-24 GeV G = 10 ^-56 GeV ^-3 x 10 ^72
=10 ^-45 GeV ^-
v

One sec. square is equal to: 10^ - 3^{8} GeV THE SAME
VALUE FOUND BY cAVENDISH IN IS EXPERIMENT.

G = 1.3 x 10 ^{-38} GeV ^{-2}

Cavendish constant of gravity G in natural units is than, G = 1.3 x l0 ^{-38}
GeV ^{-2} IThe established value in GeV in the electron implosion wave, we have assumed that it acquires an ultimate
minimum linear dimension dei equal to 10 ^{-53} m at a distance from the source center of: 10 ^{-l0} m with
an energy of action Et equal to a negative value of the Planck constant -h x GeV ^{-3}.

One second in natural units is l0 ^{-24} GeV, h is equal to one. The dimension
dei in natural units Was estimated byy me to 10 ^{-53} GeV ^{-1} . Since light with a velocity C
in natural units has a value equal to 1, the time taken to traverse di is also equal to

10 ^{-38} GeV ^{-}1 Cavendish value of G is given in:

cubic meters / Kilograms / squared second volume / energy
of action / time squared

The cubic volume
Vi of side equal to l0^{ -53} m has a value of

Vi = (10 ^{-38} GeV ^{-1})^{3}
x GeV ^{-3}

The energy of action Eit in the first gravity wave has a negative value of:

-Eit = -(h x GeV ^{-3}) Vi/Eit
= 10 ^{-114} Gev ^{-3} / GeV ^{-3}

G = (10 ^{-38}) ^{3} GeV ^{-3} / - (h x GeV ^{-3}) / (I0 ^{-38}) ^{2}
GeV ^{-2}

G = l0 ^{-114} GeV ^{-3} / GeV ^{-3}
/ I0 ^{-76} GeV ^{-2}

G = 10 ^{-114}/10 ^{-76} GeV ^{-1}
G = 10 ^{-38} GeV ^{-2 SAME VALUE FOUND ESPERIMENTALLY }

The constant G equal to 10 ^{-38} GeV ^{-2}
natural units as measured by Cavendish can be interpreted as V/Et/t ^{2}. 10 ^{-114} GeV ^{-3} / (h
x GeV ^{-3}) / (l0 ^{-76} GeV ^{-2}) =

10 ^{-38} GeV ^{-2} The volume of l0 ^{-53} m ^{3} divided by the energy of action
in the first implosion wave divided by the time taken by light to cross its linear dimension squared These results tend to
confinn the viability of my hypothesis regarding the assumed physical dimensions and the mechanical dynamic of a Source.

*Henry Cavendish determined the value of the gravity
constant through a very delicate experiment. He suspended a rod by the middle with a light torsion wire, at the ends of the
rod he put two small lead balls. Cavendish then calibrated the wire, so that he could register the amount of torsion generated
by applying very tiny forces to it. He than put two large lead balls at a close distance from the small balls and registered
the amount of the twist torsion over the suspension wire. Newton law of gravitation can be expressed by the fonnula

Fg = G x M x m /d ^{2} (I still consider gravity as a force)

With the value of Fg so determined, knowing the masses' M and m and their distance d, the value of G could be and
was detennined.